(0.5-x)^2/(2x)^2=0.28x

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Solution for (0.5-x)^2/(2x)^2=0.28x equation: 



(0.5-x)^2/(2x)^2=0.28x

We move all terms to the left:

(0.5-x)^2/(2x)^2-(0.28x)=0



Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

(-1x+0.5)^2/2x^2-(+0.28x)=0

We get rid of parentheses

(-1x+0.5)^2/2x^2-0.28x=0

We multiply all the terms by the denominator


(-1x+0.5)^2-(0.28x)*2x^2=0

We add all the numbers together, and all the variables

(-1x+0.5)^2-(+0.28x)*2x^2=0

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